0.48x^2-0.2x-1=0

Solution for 0.48x^2-0.2x-1=0 equation:

0.48x^2-0.2x-1=0

a = 0.48; b = -0.2; c = -1;
Δ = b2-4ac
Δ = -0.22-4·0.48·(-1)
Δ = 1.96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.2)-\sqrt{1.96}}{2*0.48}=\frac{0.2-\sqrt{1.96}}{0.96}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.2)+\sqrt{1.96}}{2*0.48}=\frac{0.2+\sqrt{1.96}}{0.96}
$